7m^2+42m-112=0

Solution for 7m^2+42m-112=0 equation:

7m^2+42m-112=0

a = 7; b = 42; c = -112;
Δ = b2-4ac
Δ = 422-4·7·(-112)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-70}{2*7}=\frac{-112}{14}
=-8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+70}{2*7}=\frac{28}{14}
=2
$